(New page: {| | align="left" style="padding-left: 0em;" | CTFT of a impulse train |- | <math> X(f)=\mathcal{X}(2\pi f)=\frac{2\pi}{T}\sum^{\infty}_{k=-\infty}\delta(2\pi f-\frac{2\pi k}{T})=\frac{1...) |
(No difference)
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Revision as of 16:45, 9 September 2010
| CTFT of a impulse train |
| $ X(f)=\mathcal{X}(2\pi f)=\frac{2\pi}{T}\sum^{\infty}_{k=-\infty}\delta(2\pi f-\frac{2\pi k}{T})=\frac{1}{T}\sum^{\infty}_{k=-\infty}\delta(f-\frac{k}{T})\ $ |
| $ Since\ k\delta (kt)=\delta (t),\forall k\ne 0 $ |
