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|<math>X(f)= \mathcal{X}(2\pi f)=2\pi \delta (2\pi f-\omega_0)</math>

Revision as of 15:55, 9 September 2010

CTFT of a complex exponential
$ X(f)= \mathcal{X}(2\pi f)=2\pi \delta (2\pi f-\omega_0) $
$ Since\text{ } k\delta (kt)=\delta (t),\forall k\ne 0 $
$ X(f)=\delta (f-\frac{\mu_0}{2\pi}) $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood