Revision as of 17:35, 1 October 2008 by Dmsnell (Talk)


Questions

$ Y(t) = x(t - 1) - x(1 - t) $


It is Time Invariant? Justify.


Answer

No.

$ S_1 = Y(t) = x(t - 1) - x(1 - t) $

$ S_2 = Y(t) = x(t - t_o) $

$ x(t) -> S1 -> S2 -> x(t - t_o - 1) - x(1 - t + t_o) $

$ x(t) -> S2 -> S1 -> x(t - t_o - 1) - x(1 - t - t_o) $

$ x(t - t_o - 1) - x(1 - t + t_o) =/= x(t - t_o - 1) - x(1 - t - t_o) $

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Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett