(New page: == Questions == <math>Y(t) = x(t - 1) - x(1 - t)</math> It is Time Invariant? Justify. == Answer == No. <math>S_1 = Y(t) = x(t - 1) - x(1 - t)</math> <math>S_2 = Y(t) = x(t - t_o)...) |
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Revision as of 20:15, 9 September 2008
Questions
$ Y(t) = x(t - 1) - x(1 - t) $
It is Time Invariant? Justify.
Answer
No.
$ S_1 = Y(t) = x(t - 1) - x(1 - t) $
$ S_2 = Y(t) = x(t - t_o) $
$ x(t) -> S1 -> S2 -> x(t - t_o - 1) - x(1 - t + t_o) $
$ x(t) -> S2 -> S1 -> x(t - t_o - 1) - x(1 - t - t_o) $
$ x(t - t_o - 1) - x(1 - t + t_o) =/= x(t - t_o - 1) - x(1 - t - t_o) $
