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<math>P_\infty = lim_{T \to \infty} \ 1/(2T) \int_{-T}^T |x(t)|^2\,dt</math> | <math>P_\infty = lim_{T \to \infty} \ 1/(2T) \int_{-T}^T |x(t)|^2\,dt</math> | ||
| − | <math>= lim_{T \to \infty} \ 1/(2T) \int_{-T}^T |\sqrt(t)|^2\,dt<math> | + | <math>= lim_{T \to \infty} \ 1/(2T) \int_{-T}^T |\sqrt(t)|^2\,dt</math> |
| + | <math>lim_{T \to \infty} \ 1/(2T) \int_{-T}^T .5*t^2|_{-T}^T</math> | ||
Revision as of 11:01, 21 June 2009
$ x(t) = \sqrt(t) $
$ x(t) = \cos(t) + \jmath\sin(t) $
$ E_\infty = \int_{-\infty}^\infty |x(t)|^2\,dt $
$ =\int_{-\infty}^\infty |\sqrt(t)|^2\,dt $ $ =\int_0^\infty t\,dt $ $ =.5*t^2|_0^\infty $ $ =.5(\infty^2 - 0^2) $
$ E_\infty = \infty $
$ P_\infty = lim_{T \to \infty} \ 1/(2T) \int_{-T}^T |x(t)|^2\,dt $
$ = lim_{T \to \infty} \ 1/(2T) \int_{-T}^T |\sqrt(t)|^2\,dt $ $ lim_{T \to \infty} \ 1/(2T) \int_{-T}^T .5*t^2|_{-T}^T $
