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<math>P_{\infty} = lim_{T\rightarrow\infty}\frac{1}{2T}\int_{-T}^{T}|x(t)|^{2}dt</math>
 
<math>P_{\infty} = lim_{T\rightarrow\infty}\frac{1}{2T}\int_{-T}^{T}|x(t)|^{2}dt</math>
  
<math>P_{\infty} = lim_{T\rightarrow\infty}\frac{1}{2T}(.5T|_{-\infty}^{0}+.5T|_{0}^{\infty})</math>
+
<math>P_{\infty} = lim_{T\rightarrow\infty}\frac{1}{2T}(.5T^{2}|_{-\infty}^{0}+.5T^{2}|_{0}^{\infty})</math>
  
 
<math>P_{\infty} = lim_{T\rightarrow\infty}\frac{1}{4}(T|_{-\infty}^{0}+T|_{0}^{\infty})</math>
 
<math>P_{\infty} = lim_{T\rightarrow\infty}\frac{1}{4}(T|_{-\infty}^{0}+T|_{0}^{\infty})</math>
  
 
<math>P_{\infty} = \infty</math>
 
<math>P_{\infty} = \infty</math>

Revision as of 08:22, 22 June 2009

$ x(t) = \sqrt{t} $

$ E_{\infty} = \int_{-\infty}^{\infty}|x(t)|^{2}dt $

$ E_{\infty} = \int_{-\infty}^{\infty}|\sqrt{t}|^{2}dt $

$ E_{\infty} = \int_{-\infty}^{\infty}t dt $

$ E_{\infty} = 1/2*t^{2}|_{-\infty}^{0}+1/2*t^{2}|_{0}^{\infty} $

$ E_{\infty} = \infty $


$ P_{\infty} = lim_{T\rightarrow\infty}\frac{1}{2T}\int_{-T}^{T}|x(t)|^{2}dt $

$ P_{\infty} = lim_{T\rightarrow\infty}\frac{1}{2T}(.5T^{2}|_{-\infty}^{0}+.5T^{2}|_{0}^{\infty}) $

$ P_{\infty} = lim_{T\rightarrow\infty}\frac{1}{4}(T|_{-\infty}^{0}+T|_{0}^{\infty}) $

$ P_{\infty} = \infty $

Alumni Liaison

has a message for current ECE438 students.

Sean Hu, ECE PhD 2009