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[[Category:ECE302Spring2013Boutin]] [[Category:ECE]] [[Category:ECE302]] [[Category:probability]] [[Category|problem solving]]
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[[Category|problem solving]]  
  
[[Category:conditional probability]]
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'''Conditional Probability'''
  
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'''Problem:'''
  
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One dice is rolled two separate times. Find the probability that the dice lands on an even number both times, and the sum of the two rolls is greater than 6 but the first roll must be larger than the second.<br>
  
One dice is rolled two separate times. Find the probability that the dice lands on an even number both times, and the sum of the two rolls is greater than 6 but the first roll must be larger than the second.<br>
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'''Solution:<br>'''
  
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The complete set would consist of the following:<br>  
  
The complete set would consist of the following:<br>
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S={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}<br>  
  
S={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}<br>
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We will let A="even number both times" and B="the sum of the two rolls is greater than 6 but the first roll must be larger than the second"<br>  
  
We will let A="even number both times" and B="the sum of the two rolls is greater than 6 but the first roll must be larger than the second"<br>
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Therefore: A={(2,2),(2,4),(2,6),(4,2),(4,4),(4,6),(6,2),(6,4),(6,6)} and B={(4,3),(5,2),(5,3),(5,4),(6,1),(6,2),(6,3),(6,4),(6,5)}<br>  
  
Therefore: A={(2,2),(2,4),(2,6),(4,2),(4,4),(4,6),(6,2),(6,4),(6,6)} and B={(4,3),(5,2),(5,3),(5,4),(6,1),(6,2),(6,3),(6,4),(6,5)}<br>
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There are 36 total outcomes, so P(AnB)={(6,2),(6,4)}=2/36 and P(B)=9/36<br>  
  
There are 36 total outcomes, so P(AnB)={(6,2),(6,4)}=2/36 and P(B)=9/36<br>
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P(A|B)=(2/36)/(9/36)= 2/9<br>  
  
P(A|B)=(2/36)/(9/36)= 2/9<br>
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[[Bonus point 1 ECE302 Spring2012 Boutin|Back to first bonus point opportunity, ECE302 Spring 2013]]
  
[[Bonus_point_1_ECE302_Spring2012_Boutin|Back to first bonus point opportunity, ECE302 Spring 2013]]
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[[Category:ECE302Spring2013Boutin]] [[Category:ECE]] [[Category:ECE302]] [[Category:Probability]] [[Category:Conditional_probability]]

Latest revision as of 19:18, 27 January 2013

problem solving 

Conditional Probability

Problem:

One dice is rolled two separate times. Find the probability that the dice lands on an even number both times, and the sum of the two rolls is greater than 6 but the first roll must be larger than the second.

_____________________________________________________________________________________________________________________________________

Solution:

The complete set would consist of the following:

S={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

We will let A="even number both times" and B="the sum of the two rolls is greater than 6 but the first roll must be larger than the second"

Therefore: A={(2,2),(2,4),(2,6),(4,2),(4,4),(4,6),(6,2),(6,4),(6,6)} and B={(4,3),(5,2),(5,3),(5,4),(6,1),(6,2),(6,3),(6,4),(6,5)}

There are 36 total outcomes, so P(AnB)={(6,2),(6,4)}=2/36 and P(B)=9/36

P(A|B)=(2/36)/(9/36)= 2/9


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