(New page: ==Solution of Week12 Quiz Question 5== ---- ---- Back to Quiz Pool Back to Lab wiki)
 
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a.
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<math>
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\begin{align}
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X[k]&=\sum_{n=0}^3 x[n]e^{-j\frac{2\pi n}{N}k} \\
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&=\sum_{n=0}^3 cos(\frac{n\pi}{2})e^{-j\frac{2\pi n}{N}k} \\
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&=1-e^{-j\pi k}\text{ , }0\le k\le 3
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\end{align}
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</math>
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b.
  
  

Revision as of 13:23, 10 November 2010

Solution of Week12 Quiz Question 5


a.

$ \begin{align} X[k]&=\sum_{n=0}^3 x[n]e^{-j\frac{2\pi n}{N}k} \\ &=\sum_{n=0}^3 cos(\frac{n\pi}{2})e^{-j\frac{2\pi n}{N}k} \\ &=1-e^{-j\pi k}\text{ , }0\le k\le 3 \end{align} $

b.



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