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[[Category:ECE301 S11 Exam 3 more practice]][[Category:ECE301 S11 Exam 3 more practice]][[Category:ECE301 S11 Exam 3 more practice]]
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[[Category:ECE301 S11 Exam 3 more practice]]
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[[Category:ECE301Spring2011Boutin]]
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[[Category:Problem_solving]]
  
=ECE301S11_more_practice_DT_conv_7_ekhall=
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= Problem =
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Compute the convolution
  
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<math>z[n]=x[n]*y[n]  \ </math>
  
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between
  
Put your content here . . .
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<math> x[n] = e^{jwn}u[n] \ </math>
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and
  
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<math> y[n] = e^{jwn}u[n-6] \ </math>.
  
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= My Solution=
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<math>
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\begin{align}
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z[n] &= x[n]*y[n]\\
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&=\sum_{k=-\infty}^{\infty}x[k]y[n-k] \\
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&=\sum_{k=-\infty}^{\infty}e^{jwk}u[k]e^{jw(n-k)}u[n-k-6] \\
  
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&=\begin{cases}
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\sum_{k=0}^{n-6}e^{jwk}e^{jwn}e^{-jwk}, & n \geq 6 \\
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0, & n < 5 \\
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\end{cases}\\
  
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&=\begin{cases}
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e^{jwn}\sum_{k=0}^{n-6}1, & n \geq 6 \\
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0, & n < 5 \\
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\end{cases}\\
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&=\begin{cases}
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e^{jwn}(n-5), & n \geq 6 \\
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0, & n < 5 \\
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\end{cases}\\
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\end{align}
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</math>
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==Comments==
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Write them here.
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----
 
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Latest revision as of 08:29, 6 May 2011


Problem

Compute the convolution

$ z[n]=x[n]*y[n] \ $

between

$ x[n] = e^{jwn}u[n] \ $

and

$ y[n] = e^{jwn}u[n-6] \ $.

My Solution

$ \begin{align} z[n] &= x[n]*y[n]\\ &=\sum_{k=-\infty}^{\infty}x[k]y[n-k] \\ &=\sum_{k=-\infty}^{\infty}e^{jwk}u[k]e^{jw(n-k)}u[n-k-6] \\ &=\begin{cases} \sum_{k=0}^{n-6}e^{jwk}e^{jwn}e^{-jwk}, & n \geq 6 \\ 0, & n < 5 \\ \end{cases}\\ &=\begin{cases} e^{jwn}\sum_{k=0}^{n-6}1, & n \geq 6 \\ 0, & n < 5 \\ \end{cases}\\ &=\begin{cases} e^{jwn}(n-5), & n \geq 6 \\ 0, & n < 5 \\ \end{cases}\\ \end{align} $

Comments

Write them here.


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