(New page: Category: ECE Category: ECE 301 Category: Summer Category: 2008 Category: asan Category: Bonus Given: <math>y[n]=x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k])</ma...) |
(No difference)
|
Latest revision as of 10:40, 21 November 2008
Given: $ y[n]=x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k]) $
- $ x[n]*(h_1[n]+h_1[n])=\sum_{k=-\infty}^{\infty}x[k](h_1[n-k]+h_2[n-k]) $
- $ x[n]*(h_1[n]+h_1[n])=\sum_{k=-\infty}^{\infty}(x[k]h_1[n-k]+x[k]h_2[n-k]) $
- $ x[n]*(h_1[n]+h_1[n])=\sum_{k=-\infty}^{\infty}x[k]h_1[n-k]+\sum_{k=-\infty}^{\infty}x[k]h_2[n-k] $
- $ x[n]*(h_1[n]+h_1[n])=x[n]*h_1[n]+x[n]*h_2[n] $
