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Let x(t) be a continuous-time signal with <math class="inline"> \left| {\mathcal X} (\omega)\right| =0</math> for <math class="inline"> \left| \omega)\right| > \omega_m </math>. Can one recover the signal x(t) from the signal <math class="inline"> y(t)=x(t) p(t-3) </math>, where | Let x(t) be a continuous-time signal with <math class="inline"> \left| {\mathcal X} (\omega)\right| =0</math> for <math class="inline"> \left| \omega)\right| > \omega_m </math>. Can one recover the signal x(t) from the signal <math class="inline"> y(t)=x(t) p(t-3) </math>, where | ||
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| + | <math class="inline"> p(t)= \sum_{k=-\infty}^\infty \delta (t- \frac{2\pi}{\omega_s} n) ?</math> | ||
Revision as of 05:36, 1 April 2011
Should question 3 be
Let x(t) be a continuous-time signal with $ \left| {\mathcal X} (\omega)\right| =0 $ for $ \left| \omega\right| > \omega_s $. Can one recover the signal x(t) from the signal $ y(t)=x(t) p(t-3) $, where
$ p(t)= \sum_{k=-\infty}^\infty \delta (t- \frac{2\pi}{\omega_s} k) ? $
instead of this?
Let x(t) be a continuous-time signal with $ \left| {\mathcal X} (\omega)\right| =0 $ for $ \left| \omega)\right| > \omega_m $. Can one recover the signal x(t) from the signal $ y(t)=x(t) p(t-3) $, where
$ p(t)= \sum_{k=-\infty}^\infty \delta (t- \frac{2\pi}{\omega_s} n) ? $
