Revision as of 05:33, 28 August 2008 by Dimberti (Talk)

I did the first one by contradiction and a lot of cases.

$ Given A, B \neq \varnothing \subseteq \mathbf{R}, A+B = \{ a+b \vert a \in A, b \ in B \} \newline WTS: \sup(A+B) = \supA + \sup B $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood