(New page: I did the first one by contradiction and a lot of cases. <math>Test, $\sup$ \sup</math>) |
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I did the first one by contradiction and a lot of cases. | I did the first one by contradiction and a lot of cases. | ||
| − | <math> | + | <math>Given A, B \neq \varnothing \subseteq \mathbf{R}, A+B = \{ a+b \vert a \in A, b \ in B \} |
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| + | WTS: \sup(A+B) = \supA + \sup B</math> | ||
Revision as of 05:33, 28 August 2008
I did the first one by contradiction and a lot of cases.
$ Given A, B \neq \varnothing \subseteq \mathbf{R}, A+B = \{ a+b \vert a \in A, b \ in B \} \newline WTS: \sup(A+B) = \supA + \sup B $
