(New page: <math>e^{jw_0n} = 2\pi\sum_{l=-\infty}^{\infty}\delta(w-w_0-2\pi l) \ </math>)
 
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<math>e^{jw_0n} = 2\pi\sum_{l=-\infty}^{\infty}\delta(w-w_0-2\pi l) \ </math>
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<math>e^{jw_0n} = 2\pi\sum_{l=-\infty}^{+\infty}\delta(w-w_0-2\pi l) \ </math>

Revision as of 14:50, 15 October 2008

$ e^{jw_0n} = 2\pi\sum_{l=-\infty}^{+\infty}\delta(w-w_0-2\pi l) \ $

Alumni Liaison

Questions/answers with a recent ECE grad

Ryne Rayburn