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| − | <math> | + | <math>sin[\omega _0 n]u[n]\rightarrow \frac{1}{2j}[\frac{1}{1-e^{-j(\omega -\omega _0)}}-\frac{1}{1-e^{-j(\omega +\omega _0)}}]</math> |
Latest revision as of 18:11, 15 October 2008
$ sin[\omega _0 n]u[n]\rightarrow \frac{1}{2j}[\frac{1}{1-e^{-j(\omega -\omega _0)}}-\frac{1}{1-e^{-j(\omega +\omega _0)}}] $
