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x[n] = <math>1/{2\pi} \int_{2\pi} X(e^{j\omega}) e^{j\omega n) d\omega</math>
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x[n] = <math>1/{2\pi} \int_{2\pi} X(e^{j\omega}) e^{j\omega n} d\omega</math>

Revision as of 07:38, 26 July 2009




D.T.F.T.



x[n] = $ 1/{2\pi} \int_{2\pi} X(e^{j\omega}) e^{j\omega n} d\omega $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood