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Compute E<math>\infty</math> and P<math>\infty</math> of x(t)=t^(1/2)
 
Compute E<math>\infty</math> and P<math>\infty</math> of x(t)=t^(1/2)
  
E<math>infty</math>  =  <math>\int</math>|<math>\sqrt{t}</math>|^2dt  =  <math>\int</math>tdt
+
E<math>\infty</math>  =  <math>\int</math>|<math>\sqrt{t}</math>|^2dt  =  <math>\int</math>tdt
 
=(t^2)/2|-<math>\infty</math>,<math>\infty</math>  =  <math>\infty</math>
 
=(t^2)/2|-<math>\infty</math>,<math>\infty</math>  =  <math>\infty</math>
  
 
P<math>\infty</math>  =  lim((1/(2*T))*<math>\int</math>|<math>\sqrt{t}</math>|^2dt)  =  lim(T-(-T))  =  <math>\infty</math>
 
P<math>\infty</math>  =  lim((1/(2*T))*<math>\int</math>|<math>\sqrt{t}</math>|^2dt)  =  lim(T-(-T))  =  <math>\infty</math>

Latest revision as of 10:58, 21 June 2009

HW_1 Xiaodian Xie 0016898772

Compute E$ \infty $ and P$ \infty $ of x(t)=t^(1/2)

E$ \infty $ = $ \int $|$ \sqrt{t} $|^2dt = $ \int $tdt =(t^2)/2|-$ \infty $,$ \infty $ = $ \infty $

P$ \infty $ = lim((1/(2*T))*$ \int $|$ \sqrt{t} $|^2dt) = lim(T-(-T)) = $ \infty $

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