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Compute E<math>\infty</math> and P<math>\infty</math> of x(t)=t^(1/2) | Compute E<math>\infty</math> and P<math>\infty</math> of x(t)=t^(1/2) | ||
| − | E<math>infty</math>=<math>\int</math>|<math>\sqrt{t}</math>|^2dt=<math>\int</math>tdt | + | E<math>infty</math> = <math>\int</math>|<math>\sqrt{t}</math>|^2dt = <math>\int</math>tdt |
| − | =(t^2)/2|-<math>\infty</math>,<math>\infty</math>=<math>\infty</math> | + | =(t^2)/2|-<math>\infty</math>,<math>\infty</math> = <math>\infty</math> |
| − | P<math>\infty</math>=lim(1/(2*T))*<math>\int</math>|<math>\sqrt{t}</math>|^2dt | + | P<math>\infty</math> = lim((1/(2*T))*<math>\int</math>|<math>\sqrt{t}</math>|^2dt) = lim(T-(-T)) = <math>\infty</math> |
Revision as of 10:55, 21 June 2009
HW_1 Xiaodian Xie 0016898772
Compute E$ \infty $ and P$ \infty $ of x(t)=t^(1/2)
E$ infty $ = $ \int $|$ \sqrt{t} $|^2dt = $ \int $tdt =(t^2)/2|-$ \infty $,$ \infty $ = $ \infty $
P$ \infty $ = lim((1/(2*T))*$ \int $|$ \sqrt{t} $|^2dt) = lim(T-(-T)) = $ \infty $
