Revision as of 18:22, 16 April 2011 by Cmcmican (Talk | contribs)


Practice Question on Computing the inverse z-transform

Compute the inverse z-transform of the following signal.

$ X(z)=\frac{1}{1+3z} \mbox{, } \Big|z\Big|<\frac{1}{3} $


Share your answers below

Prof. Mimi gave me this problem in class on Friday, so I'm posting it and my answer here. --Cmcmican 22:22, 16 April 2011 (UTC)


Answer 1

$ X(z)=\sum_{k=0}^\infty (-3z)^k=\sum_{k=-\infty}^\infty u[k](-3)^kz^k $

let n=-k

$ =\sum_{n=-\infty}^\infty u[-n](-3)^{-n} z^{-n} $

By comparison with $ \sum_{n=-\infty}^\infty x[n] z^{-n}: $

$ x[n]=(-3)^{-n}u[-n]\, $

--Cmcmican 22:22, 16 April 2011 (UTC)

Answer 2

Write it here.

Answer 3

Write it here.


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