(New page: Category:MA453Spring2009Walther If g^k=1 then dividing by g^k you get g^(-k)=1. So ord(1/g) is less than or equal to ord(g). This goes both ways, so equality must hold. --~~~~) |
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--[[User:Awika|Awika]] 14:42, 30 January 2009 (UTC) | --[[User:Awika|Awika]] 14:42, 30 January 2009 (UTC) | ||
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Revision as of 10:00, 1 February 2009
If g^k=1 then dividing by g^k you get g^(-k)=1. So ord(1/g) is less than or equal to ord(g). This goes both ways, so equality must hold.
--Awika 14:42, 30 January 2009 (UTC)
