(New page: In the field Z5, we can see by trial and error that the polynomial x^2-2 is irreducible. Therefore Z5[x]/<x^2-2> is a field, it has 5^2 elements. -Sarah ---------------------------------) |
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Revision as of 09:16, 12 November 2008
In the field Z5, we can see by trial and error that the polynomial x^2-2 is irreducible. Therefore Z5[x]/<x^2-2> is a field, it has 5^2 elements. -Sarah
