(New page: *I am kinda lost in this chapter. Could someone enlighten me on this question? I missed one of the lecture.<br> -Wooi-Chen Ng)
 
 
(3 intermediate revisions by 2 users not shown)
Line 1: Line 1:
 
*I am kinda lost in this chapter. Could someone enlighten me on this question? I missed one of the lecture.<br>
 
*I am kinda lost in this chapter. Could someone enlighten me on this question? I missed one of the lecture.<br>
 
-Wooi-Chen Ng
 
-Wooi-Chen Ng
 +
 +
I can prove part a if p is prime, but I'm not sure how to prove that p is prime.  Any ideas?
 +
 +
 +
Not too sure if this is right:  Please, correct me if I am wrong.
 +
 +
Let X = x^(p^(n-1)) and Let Y = y^(p^(n-1))
 +
 +
From part a & induction:
 +
 +
(X+Y)^p = X^p + Y^p = x^p^n + y^p^n
 +
 +
and
 +
 +
(X+Y)^p = (x^(p^(n-1))+y^(p^(n-1)))^p = (x+y)^p^n = x^p^n + y^p^n.
 +
 +
 +
 +
The part C.
 +
P should be a prime number.
 +
(x+y)^4 = x^4 + 4x^3y + 6x^2y^2 + 4xy^3 + y^4
 +
so, it could be any number that is not prime.
 +
-Soo

Latest revision as of 05:07, 30 October 2008

  • I am kinda lost in this chapter. Could someone enlighten me on this question? I missed one of the lecture.

-Wooi-Chen Ng

I can prove part a if p is prime, but I'm not sure how to prove that p is prime. Any ideas?


Not too sure if this is right: Please, correct me if I am wrong.

Let X = x^(p^(n-1)) and Let Y = y^(p^(n-1))

From part a & induction:

(X+Y)^p = X^p + Y^p = x^p^n + y^p^n

and

(X+Y)^p = (x^(p^(n-1))+y^(p^(n-1)))^p = (x+y)^p^n = x^p^n + y^p^n.


The part C. P should be a prime number. (x+y)^4 = x^4 + 4x^3y + 6x^2y^2 + 4xy^3 + y^4 so, it could be any number that is not prime. -Soo

Alumni Liaison

Sees the importance of signal filtering in medical imaging

Dhruv Lamba, BSEE2010