(New page: Category:MA453Spring2009Walther Generally speaking, 2x2 matrices have the form {(a,b), (c,d)} where (a,b) is the first row and (c,d) is the second. The inverse of any 2x2 matrix, M, ...) |
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Generally speaking, 2x2 matrices have the form {(a,b), (c,d)} where (a,b) is the first row and (c,d) is the second. The inverse of any 2x2 matrix, M, is just 1/det(M)*{(d,-b), (-c,a)} and the det(M) is just ad-bc. This means that every 2x2 matrix, M, has an inverse unless ad-bc=0.<br> | Generally speaking, 2x2 matrices have the form {(a,b), (c,d)} where (a,b) is the first row and (c,d) is the second. The inverse of any 2x2 matrix, M, is just 1/det(M)*{(d,-b), (-c,a)} and the det(M) is just ad-bc. This means that every 2x2 matrix, M, has an inverse unless ad-bc=0.<br> | ||
--[[User:Jniederh|Jniederh]] 02:16, 11 March 2009 (UTC) | --[[User:Jniederh|Jniederh]] 02:16, 11 March 2009 (UTC) | ||
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| + | Doesn't ad-bc also have to divide each of a, b, c, and d? Otherwise the inverse of the matrix would have fractional elements and therefore would not be in <math>M_2(Z)</math>.--[[User:Mkorb|Mkorb]] 23:17, 11 March 2009 (UTC) | ||
Revision as of 19:17, 11 March 2009
Generally speaking, 2x2 matrices have the form {(a,b), (c,d)} where (a,b) is the first row and (c,d) is the second. The inverse of any 2x2 matrix, M, is just 1/det(M)*{(d,-b), (-c,a)} and the det(M) is just ad-bc. This means that every 2x2 matrix, M, has an inverse unless ad-bc=0.
--Jniederh 02:16, 11 March 2009 (UTC)
Doesn't ad-bc also have to divide each of a, b, c, and d? Otherwise the inverse of the matrix would have fractional elements and therefore would not be in $ M_2(Z) $.--Mkorb 23:17, 11 March 2009 (UTC)
