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<math> x(t) = \delta (t+1) + \delta (t-1) </math>
 
<math> x(t) = \delta (t+1) + \delta (t-1) </math>
  
<math> X(\omega) = \int_{-\infty}^{\infty} \delta (t+1)e^{-j\omegat} </math>
+
<math> X(\omega) = \int_{-\infty}^{\infty} \delta (t+1)e^{-j \omega t} </math>

Revision as of 18:05, 24 October 2008

Fourier Transform of delta functions

$ x(t) = \delta (t+1) + \delta (t-1) $

$ X(\omega) = \int_{-\infty}^{\infty} \delta (t+1)e^{-j \omega t} $

Alumni Liaison

Recent Math PhD now doing a post-doctorate at UC Riverside.

Kuei-Nuan Lin