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<math>x(t)=4\cos(t)+4\jmath\sin(t)</math>
  
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Compute magnitude of <math>x(t)</math>
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  <math>|x(t)|=|4\cos(t)+4\jmath\sin(t)|</math>
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  <math>|x(t)|=\sqrt{16\cos^2(t)+16\sin^2(t)}=4</math>
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Compute <math>E\infty</math>
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  <math>E\infty=\int_{-\infty}^\infty |4|^2\,dt</math>
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  <math>E\infty=16t|_{-\infty}^\infty</math>
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  <math>E\infty=\infty</math>
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Compute <math>P\infty</math>
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  <math>P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}\int|4|^2dt</math>
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  <math>P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}*16|_{-T}^T</math>
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  <math>P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}*16(T-(-T))</math>
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  <math>P\infty=lim_{T \to \infty} \ 16</math>
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  <math>P\infty=16</math>

Latest revision as of 19:29, 21 June 2009

$ x(t)=4\cos(t)+4\jmath\sin(t) $

Compute magnitude of $ x(t) $

  $ |x(t)|=|4\cos(t)+4\jmath\sin(t)| $
  $ |x(t)|=\sqrt{16\cos^2(t)+16\sin^2(t)}=4 $ 

Compute $ E\infty $

  $ E\infty=\int_{-\infty}^\infty |4|^2\,dt $
  
  $ E\infty=16t|_{-\infty}^\infty $
  $ E\infty=\infty $

Compute $ P\infty $

  $ P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}\int|4|^2dt $
  $ P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}*16|_{-T}^T $
  $ P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}*16(T-(-T)) $
  $ P\infty=lim_{T \to \infty} \ 16 $
  $ P\infty=16 $

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