| Line 3: | Line 3: | ||
<math>|x(t)|=|4\cos(t)+4\jmath\sin(t)|</math> | <math>|x(t)|=|4\cos(t)+4\jmath\sin(t)|</math> | ||
<math>|x(t)|=\sqrt{16\cos^2(t)+16\sin^2(t)}</math> | <math>|x(t)|=\sqrt{16\cos^2(t)+16\sin^2(t)}</math> | ||
| − | <math>x(t)=4 | + | <math>|x(t)|=4</math> |
Compute <math>E\infty</math> | Compute <math>E\infty</math> | ||
Revision as of 19:00, 21 June 2009
$ x(t)=4\cos(t)+4\jmath\sin(t) $
$ |x(t)|=|4\cos(t)+4\jmath\sin(t)| $ $ |x(t)|=\sqrt{16\cos^2(t)+16\sin^2(t)} $ $ |x(t)|=4 $
Compute $ E\infty $
$ E\infty=\int_{-\infty}^\infty |4|^2\,dt=16t|_{-\infty}^\infty $
$ E\infty=\infty $
Compute $ P\infty $
$ P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}\int|4|^2dt $
$ P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}*16|_{-T}^T $
$ P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}*16(T-(-T)) $
$ P\infty=lim_{T \to \infty} \ 16 $
$ P\infty=16 $
