Line 5: Line 5:
 
   <math>|x(t)|=\sqrt{16\cos^2(t)+16\sin^2(t)}</math>
 
   <math>|x(t)|=\sqrt{16\cos^2(t)+16\sin^2(t)}</math>
 
    
 
    
   <math>|x(t)|=4</math>
+
   <math>|x(t)|==4</math>
  
 
Compute <math>E\infty</math>
 
Compute <math>E\infty</math>

Revision as of 18:51, 21 June 2009

$ x(t)=4\cos(t)+4\jmath\sin(t) $

$ |x(t)|=|4\cos(t)+4\jmath\sin(t)| $

 $ |x(t)|=\sqrt{16\cos^2(t)+16\sin^2(t)} $
 
 $ |x(t)|==4 $

Compute $ E\infty $

 $ E\infty=\int_{-\infty}^\infty |4|^2\,dt=16t|_{-\infty}^\infty $
 $ E\infty=\infty $

Compute $ P\infty $

 $ P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}\int|4|^2dt $
 $ P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}*16|_{-T}^T $
 $ P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}*16(T-(-T)) $
 $ P\infty=lim_{T \to \infty} \ 16 $
 $ P\infty=16 $

Alumni Liaison

Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett