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<math>x(t)=4\cos(t)+4\jmath\sin(t)</math>
 
<math>x(t)=4\cos(t)+4\jmath\sin(t)</math>
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<math>|x(t)|=|4\cos(t)+4\jmath\sin(t)|=\sqrt{16\cos^2(t)+16\sin^2(t)}=4</math>  
 
<math>|x(t)|=|4\cos(t)+4\jmath\sin(t)|=\sqrt{16\cos^2(t)+16\sin^2(t)}=4</math>  

Revision as of 18:46, 21 June 2009

$ x(t)=4\cos(t)+4\jmath\sin(t) $

$ |x(t)|=|4\cos(t)+4\jmath\sin(t)|=\sqrt{16\cos^2(t)+16\sin^2(t)}=4 $

 Compute $ E\infty $
   $ E\infty=\int_{-\infty}^\infty |4|^2\,dt=16t|_{-\infty}^\infty $
   $ E\infty=\infty $
 Compute $ P\infty $
   $ P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}\int|4|^2dt $
   $ P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}*16|_{-T}^T $
   $ P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}*16(T-(-T)) $
   $ P\infty=lim_{T \to \infty} \ 16 $
   $ P\infty=16 $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood