(New page: <math>x(t)=4\cos(t)+4\jmath\sin(t)</math> ---- Compute <math>E\infty</math> <math>|x(t)|=|4\cos(t)+4\jmath\sin(t)|=\sqrt{16\cos^2(t)+16\sin^2(t)}=4</math> <math>E\infty=\int_{-\infty}...) |
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Compute <math>E\infty</math> | Compute <math>E\infty</math> | ||
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<math>|x(t)|=|4\cos(t)+4\jmath\sin(t)|=\sqrt{16\cos^2(t)+16\sin^2(t)}=4</math> | <math>|x(t)|=|4\cos(t)+4\jmath\sin(t)|=\sqrt{16\cos^2(t)+16\sin^2(t)}=4</math> | ||
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<math>E\infty=\infty</math> | <math>E\infty=\infty</math> | ||
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Compute <math>P\infty</math> | Compute <math>P\infty</math> | ||
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<math>P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}\int|4|^2dt</math> | <math>P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}\int|4|^2dt</math> | ||
Revision as of 18:35, 21 June 2009
$ x(t)=4\cos(t)+4\jmath\sin(t) $
Compute $ E\infty $
$ |x(t)|=|4\cos(t)+4\jmath\sin(t)|=\sqrt{16\cos^2(t)+16\sin^2(t)}=4 $
$ E\infty=\int_{-\infty}^\infty |4|^2\,dt=16t|_{-\infty}^\infty $
$ E\infty=\infty $
Compute $ P\infty $
$ P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}\int|4|^2dt $
$ P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}*16|_{-T}^T $
$ P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}*16(T-(-T)) $
$ P\infty=lim_{T \to \infty} \ 16 $
$ P\infty=16 $
