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temp
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<math>x(t)=\sqrt(2t)</math>
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Compute <math>E\infty</math>
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<math>E\infty=\int_{-\infty}^\infty |x(t)|^2dt</math>
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<math>E\infty=\int_{-\infty}^\infty |\sqrt(2t)|^2dt</math>
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<math>E\infty=\int_{-\infty}^\infty |2t|dt</math>
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<math>E\infty=|t^2|_{-\infty}^{\infty}</math>
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<math>E\infty= \infty-\infty</math>
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<math>E\infty=0</math>
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-Tylor Thompson
 
-Tylor Thompson

Revision as of 17:55, 21 June 2009

$ x(t)=\sqrt(2t) $

Compute $ E\infty $

$ E\infty=\int_{-\infty}^\infty |x(t)|^2dt $

$ E\infty=\int_{-\infty}^\infty |\sqrt(2t)|^2dt $

$ E\infty=\int_{-\infty}^\infty |2t|dt $

$ E\infty=|t^2|_{-\infty}^{\infty} $

$ E\infty= \infty-\infty $

$ E\infty=0 $


-Tylor Thompson

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood