(New page: <math>x(t)=\cos(t)+\jmath\sin(t)</math> ---- <math>|x(t)|=|\cos(t)+\jmath\sin(t)|=\sqrt{\cos^2(t)+\sin^2(t)}=\sqrt{2}</math> <math>E\infty=\int_{-\infty}^\infty |\sqrt{2}|^2\,dt=2t|_...)
 
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Magnitude
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<math>|x(t)|=|\cos(t)+\jmath\sin(t)|=\sqrt{\cos^2(t)+\sin^2(t)}=\sqrt{2}</math>
 
<math>|x(t)|=|\cos(t)+\jmath\sin(t)|=\sqrt{\cos^2(t)+\sin^2(t)}=\sqrt{2}</math>
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<math>E\infty</math>
  
 
     <math>E\infty=\int_{-\infty}^\infty |\sqrt{2}|^2\,dt=2t|_{-\infty}^\infty</math>
 
     <math>E\infty=\int_{-\infty}^\infty |\sqrt{2}|^2\,dt=2t|_{-\infty}^\infty</math>
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     <math>E\infty=\infty</math>
 
     <math>E\infty=\infty</math>
  
   
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<math>P\infty</math>
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     <math>P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}\int|2|^2dt</math>
 
     <math>P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}\int|2|^2dt</math>
  

Revision as of 19:12, 21 June 2009

$ x(t)=\cos(t)+\jmath\sin(t) $


Magnitude

$ |x(t)|=|\cos(t)+\jmath\sin(t)|=\sqrt{\cos^2(t)+\sin^2(t)}=\sqrt{2} $


$ E\infty $

   $ E\infty=\int_{-\infty}^\infty |\sqrt{2}|^2\,dt=2t|_{-\infty}^\infty $
   $ E\infty=\infty $


$ P\infty $

   $ P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}\int|2|^2dt $
   $ P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}*2|_{-T}^T $
   $ P\infty=lim_{T \to \infty} \ \frac{1}{(2T)}*2(T-(-T)) $
   $ P\infty=lim_{T \to \infty} \ 2 $
   $ P\infty=2 $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood