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<math>P_\infty = lim_{T \to \infty} \ \frac{1}{2T} \frac{t^3}{3}\bigg]_0^\infty</math>
 
<math>P_\infty = lim_{T \to \infty} \ \frac{1}{2T} \frac{t^3}{3}\bigg]_0^\infty</math>
 +
 +
<math>P_\infty = \infty</math>

Revision as of 19:54, 21 June 2009

$ x(t)=tu(t) $

$ E_\infty = \int_{-\infty}^\infty |tu(t)|^2\,dt) $

$ E_\infty = \int_{0}^\infty t^2\,dt) $

$ E_\infty =\frac{t^3}{3}\bigg]_0^\infty) $

$ E_\infty =\infty-0 = \infty $

$ P_\infty = lim_{T \to \infty} \ \frac{1}{2T} \int_{-T}^T |tu(t)|^2\,dt $

$ P_\infty = lim_{T \to \infty} \ \frac{1}{2T} \int_{0}^T t^2\,dt $

$ P_\infty = lim_{T \to \infty} \ \frac{1}{2T} \frac{t^3}{3}\bigg]_0^\infty $

$ P_\infty = \infty $

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Ruth Enoch, PhD Mathematics