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  • (cur | prev) 19:29, 6 October 2008Thomas34 (Talk). . (553 bytes) (+195)
  • (cur | prev) 17:18, 6 October 2008Bjcarter (Talk). . (358 bytes) (+358). . (New page: Spencer, I am skeptical about your formula. you posted: <math>\sum_{i=1}^n\frac{n}{n - i + 1}\!</math> being equal to <math>\sum_{i=1}^n a_i = \frac{n(a_1+a_n)}{2}\!</math> Try n=...)

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Questions/answers with a recent ECE grad

Ryne Rayburn