(New page: X is a geometric random variable. We know that for geom. R.V. <math>E[X] = {1 \over P(X)}</math> The probability would of course be 1/n.) |
m (2a Spencer Mitchell moved to 4.2a Spencer Mitchell: Improperly named originally) |
(No difference)
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Latest revision as of 07:44, 15 October 2008
X is a geometric random variable. We know that for geom. R.V.
$ E[X] = {1 \over P(X)} $
The probability would of course be 1/n.
