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| − | The E[x] equation you come up with in this problem can be simplified (rid the summation term) by using a differentiated | + | The E[x] equation you come up with in this problem can be simplified (rid the summation term) by using a differentiated form of the commonly used geometric series equation: <math>\sum_{n=0}^\infty r^n = 1/(1-r)</math> |
Now take the derivative with respect to r and you get: | Now take the derivative with respect to r and you get: | ||
| − | <math>\sum_{n=0}^\infty nr^ | + | <math>\sum_{n=0}^\infty nr^{n-1} = 1/(1-r)^2</math> |
You can use this equation to simplify your expected value. | You can use this equation to simplify your expected value. | ||
Latest revision as of 07:43, 15 October 2008
The E[x] equation you come up with in this problem can be simplified (rid the summation term) by using a differentiated form of the commonly used geometric series equation: $ \sum_{n=0}^\infty r^n = 1/(1-r) $
Now take the derivative with respect to r and you get:
$ \sum_{n=0}^\infty nr^{n-1} = 1/(1-r)^2 $
You can use this equation to simplify your expected value.
