(New page: The equation of the system is y(t)= t * x(-t) the example in the problem tells us that <math>e^2jt</math> = t * <math>e^-2jt</math> and <math>e^-2jt</math> = t * <math>e^2jt</math>) |
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<math>e^-2jt</math> = t * <math>e^2jt</math> | <math>e^-2jt</math> = t * <math>e^2jt</math> | ||
| + | |||
| + | Therefore, for x(t)=cos(2t) | ||
| + | |||
| + | we have, | ||
| + | |||
| + | y(t)= t cos(-2t) | ||
| + | = t cos(2t) ( as we know that cos(-t)= cos (t)) | ||
Latest revision as of 14:15, 19 September 2008
The equation of the system is
y(t)= t * x(-t)
the example in the problem tells us that $ e^2jt $ = t * $ e^-2jt $
and
$ e^-2jt $ = t * $ e^2jt $
Therefore, for x(t)=cos(2t)
we have,
y(t)= t cos(-2t)
= t cos(2t) ( as we know that cos(-t)= cos (t))
