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**initial given statements copied from Jeff Kubascik | **initial given statements copied from Jeff Kubascik | ||
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| + | Since, | ||
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| + | <math>\cos(2t) = \frac {e^{i2t} + e^{-i2t}} {2} </math> | ||
Revision as of 15:23, 19 September 2008
We are told that a system is linear and given inputs
$ \,x_1(t)=e^{2jt}\, $ yields $ \,y_1(t)=te^{-2jt}\, $
$ \,x_2(t)=e^{-2jt}\, $ yields $ \,y_2(t)=te^{2jt}\, $
- initial given statements copied from Jeff Kubascik
Since,
$ \cos(2t) = \frac {e^{i2t} + e^{-i2t}} {2} $
