(2 intermediate revisions by the same user not shown)
Line 1: Line 1:
 
According to the following equations :
 
According to the following equations :
  
<math>exp(2jt)=t   exp(-2jt)</math>
+
<math>exp(2jt)=t* exp(-2jt)</math>
  
 
and
 
and
  
<math>exp(-2jt)=t   exp(2jt)</math>
+
<math>exp(-2jt)=t exp(2jt)</math>
 +
we see that the system equation is:
 +
 
 +
<math>x(-t)->t*x(t)</math>
 +
in case of cosine function
 +
<math>cos(t)->t*cos(t)</math>
 +
<math>cos(-t)->*cos(-t)</math>
 +
thus
 +
<math>cos(-t)=t*cos(t)</math>hence it is an even function

Latest revision as of 21:26, 17 September 2008

According to the following equations :

$ exp(2jt)=t* exp(-2jt) $

and

$ exp(-2jt)=t * exp(2jt) $

we see that the system equation is:

$ x(-t)->t*x(t) $

in case of cosine function
$ cos(t)->t*cos(t) $

$ cos(-t)->*cos(-t) $ thus $ cos(-t)=t*cos(t) $hence it is an even function

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang