(New page: <math>P[C=1 | A=0]=P[B=1]=p</math> <math>P[C=1 | A=1]=P[B=0]=1-p</math> Since p isn't equal to 1-p, the two events aren't independent.)
 
 
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<math>P[C=1 | A=0]=P[B=1]=p</math>
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<math>P[C=1 | A=0]=P[B=1]=p \,</math>
  
<math>P[C=1 | A=1]=P[B=0]=1-p</math>
+
<math>P[C=1 | A=1]=P[B=0]=1-p \,</math>
  
 
Since p isn't equal to 1-p, the two events aren't independent.
 
Since p isn't equal to 1-p, the two events aren't independent.

Latest revision as of 07:11, 17 September 2008

$ P[C=1 | A=0]=P[B=1]=p \, $

$ P[C=1 | A=1]=P[B=0]=1-p \, $

Since p isn't equal to 1-p, the two events aren't independent.

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