(New page: This problem is easy when you remember the example gone over in class. P(A=1)=1/2 P(B=1)=p C = A xor B The way i did it was to prove whether P(C=1|A=1)= P(C=1)*P(A=1) Also P(C=1|A=1) = P...)
(No difference)

Revision as of 06:25, 17 September 2008

This problem is easy when you remember the example gone over in class. P(A=1)=1/2 P(B=1)=p C = A xor B

The way i did it was to prove whether P(C=1|A=1)= P(C=1)*P(A=1)

Also P(C=1|A=1) = P(B=0) = 1-p

find P(C=1) and multiply it by P(A=1) and check if it is equal to 1-p

Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva