Revision as of 07:30, 5 September 2008 by Serekson (Talk)

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Energy of a CT signal

$ E = \int_{t1}^{t2} |x(t)|^2\ dt \! $

Power of a CT signal

$ P = \frac{1}{t2-t1} \int_{t2}^{t1} |f(t)|^2\ dt \! $

Energy of a DT signal

$ E = \sum_{n=n1}^{n2} |x[n]|^2 $

Power of a DT signal

This one may not be right, I took an educated guess $ P = \frac{1}{n2-n1+1} \sum_{n=n1}^{n2} |x[n]|^2 $

Alumni Liaison

Questions/answers with a recent ECE grad

Ryne Rayburn