$ x(t)=\sqrt{t} $
$ E\infty=\int|x(t)|^2dt $ (from $ -\infty $ to $ \infty $)
$ E\infty=\int|\sqrt{t}|^2dt=\int tdt $(from $ 0 $ to $ \infty $ due to sqrt limiting to positive Real numbers) $ E\infty=.5*t^2| $(from $ 0 $ to $ \infty $) $ E\infty=.5(\infty^2-0^2)=\infty $
