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$ x(t)=\sqrt{t} $

$ E\infty=\int|x(t)|^2dt $ (from $ -\infty $ to $ \infty $)

   $ E\infty=\int|\sqrt{t}|^2dt=\int tdt $(from $ 0 $ to $ \infty $ due to sqrt limiting to positive Real numbers)

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang