Revision as of 19:55, 1 July 2008 by Rvalluri (Talk)

Solution to Prob 4.4b

Its given that X(jw) =

$ ~2, ~~0 \le \omega \le 2 $

$ -2, ~~-2 \le \omega < 0 $

$ ~0, ~~|\omega| > 2 $

$ \therefore x(t) = \frac {1}{2\pi} \int_{-\infty}^{\infty} X(j\omega) e^{jt\omega}\,d\omega $

Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva