Revision as of 15:17, 24 June 2008 by Krtownse (Talk)

(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Given: $ y[n]=x[n]*h[n]=\sum_{k=-\infty}^\infty(x[k]h[n-k]) $

  1. $ x[n]*h[n]=\sum_{k=-\infty}^\infty(x[k]h[n-k]) $
  2. $ k'=n-k $
  3. $ x[n]*h[n]=\sum_{k=\infty}^-\infty(x[n-k']h[k']) $ from 1 and 2
  4. $ x[n]*h[n]=\sum_{k=-\infty}^\infty(x[k]h[n-k]) $
  5. $ x[n]*h[n]=h[n]*x[n] $

Alumni Liaison

has a message for current ECE438 students.

Sean Hu, ECE PhD 2009