Revision as of 07:53, 5 September 2008 by Johns311 (Talk)

Energy

The formula for the energy of this signal is given by:

$ E=\int_{0}^{\infty}{e^{-4t}u(t)dt} $

Which has the solution of $ 1/4 $

Power

The power of this signal is 0 because the energy of the signal is not $ \infty $

Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva