Revision as of 15:04, 4 September 2008 by Jkkietzm (Talk)

Energy of a Signal

$ y = 3e^{t} $ from (0,5)
$ Energy = \int_{t1}^{t2} x(t) $
$ Energy = \int_{0}^{5}3e^{t}dt $
$ Energy = 3e^{5} - 3 $


Power of a Signal

$ y = 3e^{t} $ from (0,5)
$ Average Power = \frac{1}{t2 - t1}\int_{t1}^{t2}x(t)^2 $
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Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang