Revision as of 05:33, 28 August 2008 by Dimberti (Talk)

I did the first one by contradiction and a lot of cases.

$ Given A, B \neq \varnothing \subseteq \mathbf{R}, A+B = \{ a+b \vert a \in A, b \ in B \} WTS: \sup(A+B) = \sup A + \sup B $

Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva