Revision as of 20:05, 9 September 2010 by Zhao148 (Talk | contribs)

(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)
multiplication property
$ \mathcal{U}(\omega)=\mathcal{X}(\omega)\mathcal{Y}(\omega) \ $
$ U(f)=X(f)Y(f) \ $

$ \begin{align} U(f) &= \mathcal{U}(2\pi f) \\ &=\mathcal{X}(2\pi f)\mathcal{Y}(2\pi f) \\ &= X(f)Y(f) \end{align} $

$ Since\ X(\alpha)=\mathcal{X}(2\pi \alpha),Y(\alpha)=\mathcal{Y}(2\pi \alpha) $

Alumni Liaison

BSEE 2004, current Ph.D. student researching signal and image processing.

Landis Huffman