Revision as of 16:46, 18 September 2008 by Huang122 (Talk)

$ e^2jt = te^(-2jt) $
$ e^2jt = te^(-2jt) $

=>$ \cos(2t)=\frac{e^2jt+e^(-2jt)}{2} $
=$ \frac{1}{2} $

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Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett